2014 Invitational C #32

For every 6 numbers (6 is LCM of 2 and 3) there are two numbers that aren't divisible by 2 or 3.  There are 335 full sets of 6 numbers less than 2013.  So that's

335*6 gets us to 2010 so we need to check 2011(not divisible), 2012(divisible), 2013(divisible).  So add one more to 670.